Quetion 6 : Consider the "in-order-issue/in-order-completion" execution sequence shown in f In Figure Decode OWE Execute 12 12 12 14 16 13 16 13 15 15 16 Write 024/06/02 11 3 4 11 12 13 13 N 15 16 a. Identify the most likely reason why I could not enter the execute fourth cycle. stage until the [2] b. Will "in-order issue/out-of-order completion" or "out-of-order issue/out-of-order completion" fix this? If so, which? Explain

 //call by refernce

#include <iostream.h>

#include <conio.h>

void main()

{

int a, b;

int &refa = a;

int &refb = b;

void swap (int &, int &);

clrscr();

cout << "Enter value a : ";

cin >> a;

cout << "Enter value b : ";

cin >> b;

cout << "Before swaping value : " << endl;

cout << "A = " << a << endl;

cout << "B = " << b << endl;

swap(refa, refb);

cout << "After swaping value :" << endl;

cout << "A = " << a << endl;

cout << "B = " << b << endl;

getch();

}

void swap(int &ref1, int &ref2)

{

int c;

c = ref1;

ref1 = ref2;

ref2 = c;

}