30.perameterized constructor

 // perameterized constructor

class employee{

int empcode;

String empnm;


employee(int code, String nm)

{

empcode = code;

empnm = nm;

}

}

class parameterized_constructor{

public static void main(String[] args) {

employee obj = new employee(12, "abc");


System.out.println("Employee code = " + obj.empcode);

System.out.println("Employee Name = " + obj.empnm);


}

}

Comments

Popular posts from this blog

Quetion 6 : Consider the "in-order-issue/in-order-completion" execution sequence shown in f In Figure Decode OWE Execute 12 12 12 14 16 13 16 13 15 15 16 Write 024/06/02 11 3 4 11 12 13 13 N 15 16 a. Identify the most likely reason why I could not enter the execute fourth cycle. stage until the [2] b. Will "in-order issue/out-of-order completion" or "out-of-order issue/out-of-order completion" fix this? If so, which? Explain

Question 5:

7.Write a program to read a list containing item name, item code and cost interactively and produce a three-column output as shown below. NAME CODE COST Turbo C++ 1001 250.95 C Primer 905 95.70 ------------- ------- ---------- ------------- ------- ---------- Note that the name and code are left-justified and the cost is right-justified with a precision of two digits. Trailing zeros are shown.