13.while loop - prime number or not

-

 //while loop - prime number or not


//prime number means number is divided by 1 and itself.


import java.util.*;


class primeornot

{

public static void main(String arg[])

{

int a, n;

Scanner obj = new Scanner(System.in);

System.out.print("Enter any number : ");

n = obj.nextInt();

a = 2;

while(a < n)

{

if(n % a == 0)

{

break;

}

a++;

}

if(a == n)

System.out.println(n + " is Prime number");

else

System.out.println(" Not Prime ");

}

}

Comments

Post a Comment

Popular posts from this blog

7.Write a program to read a list containing item name, item code and cost interactively and produce a three-column output as shown below. NAME CODE COST Turbo C++ 1001 250.95 C Primer 905 95.70 ------------- ------- ---------- ------------- ------- ---------- Note that the name and code are left-justified and the cost is right-justified with a precision of two digits. Trailing zeros are shown.

-
 /*J_4_P_8 Write a program to read a list containing item name, item code and cost interactively and produce a three-column output as shown below. NAME                CODE      COST ======================= Turbo C++        1001          250.95 C Primer              905           95.70 ------------- ------- ----------------- ------------- ------- ----------------- Note that the name and code are left-justified and the cost is right-justified with a precision of two digits. Trailing zeros are shown. */ #include <iostream.h> #include <iomanip.h> #include <string.h> #include <conio.h> class item {         char name[40];         int code;         float cost; public:         void get_data(char *n, int c, float co)...
Read more

Quetion 6 : Consider the "in-order-issue/in-order-completion" execution sequence shown in f In Figure Decode OWE Execute 12 12 12 14 16 13 16 13 15 15 16 Write 024/06/02 11 3 4 11 12 13 13 N 15 16 a. Identify the most likely reason why I could not enter the execute fourth cycle. stage until the [2] b. Will "in-order issue/out-of-order completion" or "out-of-order issue/out-of-order completion" fix this? If so, which? Explain

-
Answer:   a. Identify the most likely reason why I could not enter the execute stage until the fourth cycle. One likely reason an instruction couldn't enter the execute stage until the fourth cycle is due to data hazards or resource conflicts: 1. Data Hazards: If the instruction depends on the result of a previous instruction that hasn't completed yet, it cannot proceed to the execute stage. This is often referred to as a Read After Write (RAW) hazard. 2. Resource Conflicts: If the required functional unit for execution (e.g., an ALU) is occupied by another instruction, the instruction will have to wait until the resource becomes available. b. Will "in-order issue/out-of-order completion" or "out-of-order issue/out-of-order completion" fix this? If so, which? Explain In-order issue/out-of-order completion  might help if the problem is related to instructions that can complete earlier being delayed by instructions that take longer to execute. This allows the...
Read more

8.odd and even number using if else.

-
 import java.util.*; class oddeven { public static void main(String arg[]) { Scanner obj = new Scanner(System.in); int no; System.out.print("Enter any no. : "); no = obj.nextInt(); if(no % 2 == 0) System.out.println(no + " is Even number"); else System.out.println(no + " is Odd number"); } }
Read more